SQL Exercise: Name of the patients, their block, floor, room number
SQL hospital Database: Exercise-28 with Solution
28. From the following tables, write a SQL query to find the name of the patients, their block, floor, and room number where they admitted.
Sample table: stay
Sample table: patient
Sample table: room
SELECT p.name AS "Patient", s.room AS "Room", r.blockfloor AS "Floor", r.blockcode AS "Block" FROM stay s JOIN patient p ON s.patient=p.ssn JOIN room r ON s.room=r.roomnumber;
Patient | Room | Floor | Block -------------------+------+-------+------- John Smith | 111 | 1 | 2 Random J. Patient | 123 | 1 | 3 Dennis Doe | 112 | 1 | 2 (3 rows)
The said query in SQL that retrieves the name of the patient, the room number they are staying in, and the floor and block of that room.
The JOIN keyword joins the patient table to the stay table based on the ssn and patient columns and the room table to the stay table based on the roomnumber and room columns.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Find the floor with the minimum available rooms.
Next SQL Exercise: Find the nurses and the block where they are booked.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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