w3resource

SQL Exercise: Find the nurses and the block where they are booked

SQL hospital Database: Exercise-29 with Solution

29. From the following tables, write a SQL query to locate the nurses and the block where they are scheduled to attend the on-call patients.Return Nurse Name as "Nurse", Block code as "Block".

Sample table: nurse


Sample table: on_call


Sample Solution:

SELECT n.name AS "Nurse",
       o.blockcode AS "Block"
FROM nurse n
JOIN on_call o ON o.nurse=n.employeeid;

Sample Output:

      Nurse      | Block
-----------------+-------
 Carla Espinosa  |     1
 Carla Espinosa  |     2
 Laverne Roberts |     3
 Paul Flowers    |     1
 Paul Flowers    |     2
 Paul Flowers    |     3
(6 rows)

Explanation:

The said query in SQL that retrieves the name of the nurse and the block they are on call for.

The JOIN clause joins the 'nurse' and 'on_call' tables based on the employeeid and nurse columns.

Practice Online


E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: Name of the patients, their block, floor, room number.
Next SQL Exercise: Make a report of specified queries.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook