SQL Exercise: Find the nurses and the block where they are booked
SQL hospital Database: Exercise-29 with Solution
29. From the following tables, write a SQL query to locate the nurses and the block where they are scheduled to attend the on-call patients.Return Nurse Name as "Nurse", Block code as "Block".
Sample table: nurse
Sample table: on_call
SELECT n.name AS "Nurse", o.blockcode AS "Block" FROM nurse n JOIN on_call o ON o.nurse=n.employeeid;
Nurse | Block -----------------+------- Carla Espinosa | 1 Carla Espinosa | 2 Laverne Roberts | 3 Paul Flowers | 1 Paul Flowers | 2 Paul Flowers | 3 (6 rows)
The said query in SQL that retrieves the name of the nurse and the block they are on call for.
The JOIN clause joins the 'nurse' and 'on_call' tables based on the employeeid and nurse columns.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Name of the patients, their block, floor, room number.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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