SQL Exercise: Find nurses who have ever been on call for room 122
SQL hospital Database: Exercise-35 with Solution
35. From the following table, write a SQL query to find out, which nurses have been on call for room 122 in the past. Return name of the nurses.
Sample table: nurse
Sample table: on_call
Sample table: room
SELECT n.name FROM nurse n WHERE employeeid IN ( SELECT oc.nurse FROM on_call oc, room r WHERE oc.blockfloor = r.blockfloor AND oc.blockcode = r.blockcode AND r.roomnumber = 122 );
name ----------------- Laverne Roberts Paul Flowers (2 rows)
The said query in SQL that selects the name of the nurse who is on-call for the same block and floor as room number 122.
In the subquery the nurse ID from the 'on_call' table, which stores information about nurses who are on call. A join builds with the 'room' table and 'on_call' table, to match the block and floor of the room number 122 with the corresponding block and floor of the nurse's on-call shift.
The outer query then selects the name of the nurse using the nurse's employee ID, which is found in the 'nurse' table.
The WHERE clause filters the nurse records based on whether their employee ID is in the list of nurse IDs returned by the subquery.
E R Diagram of Hospital Database:
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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