SQL Exercise: Patients who have been prescribed some medication
SQL hospital Database: Exercise-36 with Solution
36. From the following table, write a SQL query to determine which patients have been prescribed medication by their primary care physician. Return Patient name as "Patient", and Physician Name as "Physician".
Sample table: patient
Sample table: prescribes
Sample table: physician
SELECT pt.name AS "Ptient", p.name AS "Physician" FROM patient pt JOIN prescribes pr ON pr.patient=pt.ssn JOIN physician p ON pt.pcp=p.employeeid WHERE pt.pcp=pr.physician AND pt.pcp=p.employeeid;
Ptient | Physician ------------+------------- John Smith | John Dorian (1 row)
This SQL query selects the names of patients and their primary care physicians (PCPs), along with the name of the physician who prescribed medication for the patient.
The first JOIN keyword links the 'patient' and 'prescribes' tables based on the patient and SSN columns. The second JOIN links the 'patient' and 'physician' tables based on the pcp and employeeid columns.
The WHERE clause includes two conditions to filter the results. The first condition ensures that the patient's PCP is also the physician who prescribed medication for the patient. The second condition ensures that the PCP employee ID matches the physician employee ID.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Find nurses who have ever been on call for room 122.
Next SQL Exercise: Patients who have had a procedure costing over $5,000.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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