SQL Exercise: Patients who have had a procedure costing over $5,000

SQL hospital Database: Exercise-37 with Solution

37. From the following table, write a SQL query to find those patients who have undergone a procedure costing more than $5,000, as well as the name of the physician who has provided primary care, should be identified. Return name of the patient as "Patient", name of the physician as "Primary Physician", and cost for the procedure as "Procedure Cost".

Sample table: patient

Sample table: undergoes

Sample table: physician

Sample table: procedure

Sample Solution:

SELECT pt.name AS " Patient ",
p.name AS "Primary Physician",
pd.cost AS " Procedure Cost"
FROM patient pt
JOIN undergoes u ON u.patient=pt.ssn
JOIN physician p ON pt.pcp=p.employeeid
JOIN PROCEDURE pd ON u.procedure=pd.code
WHERE pd.cost>5000;

Sample Output:

   Patient   | Primary Physician | Procedure Cost
 John Smith | John Dorian       |           5600
 Dennis Doe | Christopher Turk  |          10000
(2 rows)


The said query in SQL that selects the names of patients, their primary care physicians (PCPs), and the cost of any medical procedures undergone by the patient that cost more than 5,000.

The first JOIN statement joins the 'patient' and 'undergoes' tables based on the ssn and patient columns, the second JOIN statement joins the 'patient' and 'physician' tables based on the patient's pcp and employeeid columns. The third JOIN statement joins the 'procedure' and 'undergoes' tables based on the code and procedure columns.

The WHERE clause includes the results for only those medical procedures with a cost greater than 5,000.

Practice Online

E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

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Previous SQL Exercise: Patients who have been prescribed some medication.
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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI


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