SQL Exercise: Find those employees who earn more than 8000
2. From the following table, write a SQL query to find those employees whose salary is higher than 8000. Return first name, last name and department number and salary.
Sample table: employees+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | EMPLOYEE_ID | FIRST_NAME | LAST_NAME | EMAIL | PHONE_NUMBER | HIRE_DATE | JOB_ID | SALARY | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | 100 | Steven | King | SKING | 515.123.4567 | 2003-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 | | 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 2005-09-21 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 102 | Lex | De Haan | LDEHAAN | 515.123.4569 | 2001-01-13 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 103 | Alexander | Hunold | AHUNOLD | 590.423.4567 | 2006-01-03 | IT_PROG | 9000.00 | 0.00 | 102 | 60 | | 104 | Bruce | Ernst | BERNST | 590.423.4568 | 2007-05-21 | IT_PROG | 6000.00 | 0.00 | 103 | 60 | | 105 | David | Austin | DAUSTIN | 590.423.4569 | 2005-06-25 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 106 | Valli | Pataballa | VPATABAL | 590.423.4560 | 2006-02-05 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 2007-02-07 | IT_PROG | 4200.00 | 0.00 | 103 | 60 | | 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 2002-08-17 | FI_MGR | 12008.00 | 0.00 | 101 | 100 | | 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 2002-08-16 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 | ...... | 206 | William | Gietz | WGIETZ | 515.123.8181 | 2002-06-07 | AC_ACCOUNT | 8300.00 | 0.00 | 205 | 110 | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
Sample Solution:
-- Selecting 'first_name', 'last_name', 'department_id', and 'salary' columns from the 'employees' table
SELECT first_name, last_name, department_id, salary
-- Specifying the table to retrieve data from ('employees')
FROM employees
-- Filtering the results based on the condition that 'salary' is greater than 8000
WHERE salary > 8000;
Sample Output:
first_name | last_name | department_id | salary ------------+------------+---------------+---------- Steven | King | 90 | 24000.00 Neena | Kochhar | 90 | 17000.00 Lex | De Haan | 90 | 17000.00 Alexander | Hunold | 60 | 9000.00 Nancy | Greenberg | 100 | 12000.00 Daniel | Faviet | 100 | 9000.00 John | Chen | 100 | 8200.00 Den | Raphaely | 30 | 11000.00 Adam | Fripp | 50 | 8200.00 John | Russell | 80 | 14000.00 Karen | Partners | 80 | 13500.00 Alberto | Errazuriz | 80 | 12000.00 Gerald | Cambrault | 80 | 11000.00 Eleni | Zlotkey | 80 | 10500.00 Peter | Tucker | 80 | 10000.00 David | Bernstein | 80 | 9500.00 Peter | Hall | 80 | 9000.00 Janette | King | 80 | 10000.00 Patrick | Sully | 80 | 9500.00 Allan | McEwen | 80 | 9000.00 Clara | Vishney | 80 | 10500.00 Danielle | Greene | 80 | 9500.00 Lisa | Ozer | 80 | 11500.00 Harrison | Bloom | 80 | 10000.00 Tayler | Fox | 80 | 9600.00 Ellen | Abel | 80 | 11000.00 Alyssa | Hutton | 80 | 8800.00 Jonathon | Taylor | 80 | 8600.00 Jack | Livingston | 80 | 8400.00 Michael | Hartstein | 20 | 13000.00 Hermann | Baer | 70 | 10000.00 Shelley | Higgins | 110 | 12000.00 William | Gietz | 110 | 8300.00 (33 rows)
Code Explanation:
The said query in SQL that retrieves first name, last name, department ID, and salary columns from the 'employees' table where the salary is greater than 8000. As a result of the query, all the rows that meet the condition stipulated in the "WHERE" clause will be returned from the 'employees' table.
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