SQL Exercise: Find employees who did two or more jobs in the past

SQL SORTING and FILTERING on HR Database: Exercise-22 with Solution

22. From the following table, write a SQL query to find those employees who worked more than two jobs in the past. Return employee id.

+-------------+------------+------------+------------+---------------+
| EMPLOYEE_ID | START_DATE | END_DATE   | JOB_ID     | DEPARTMENT_ID |
+-------------+------------+------------+------------+---------------+
|         102 | 2001-01-13 | 2006-07-24 | IT_PROG    |            60 |
|         101 | 1997-09-21 | 2001-10-27 | AC_ACCOUNT |           110 |
|         101 | 2001-10-28 | 2005-03-15 | AC_MGR     |           110 |
|         201 | 2004-02-17 | 2007-12-19 | MK_REP     |            20 |
|         114 | 2006-03-24 | 2007-12-31 | ST_CLERK   |            50 |
|         122 | 2007-01-01 | 2007-12-31 | ST_CLERK   |            50 |
|         200 | 1995-09-17 | 2001-06-17 | AD_ASST    |            90 |
|         176 | 2006-03-24 | 2006-12-31 | SA_REP     |            80 |
|         176 | 2007-01-01 | 2007-12-31 | SA_MAN     |            80 |
|         200 | 2002-07-01 | 2006-12-31 | AC_ACCOUNT |            90 |
+-------------+------------+------------+------------+---------------+

Sample Solution:

-- Selecting 'employee_id' from the 'job_history' table
SELECT employee_id
-- Specifying the table to retrieve data from ('job_history')
FROM job_history
-- Grouping the results by 'employee_id'
GROUP BY employee_id
-- Filtering the grouped results based on the condition that the count of records for each employee is greater than or equal to 2
HAVING COUNT(*) >= 2;

Sample Output:

 employee_id
-------------
         101
         176
         200
(3 rows)

Code Explanation:

The said query in SQL that is selecting the "employee_id" from the 'job_history' table, grouping the results by the "employee_id" column, and only returning the groups that have a count of 2 or more records. In other words, it returns the "employee_id" values of employees who have changed jobs at least twice based on the records in the "job_history" table.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Query Visualization:

Duration:

Rows:

Cost:

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