# SQL Exercise: Number of orders booked for each day

## SQL Formatting Output: Exercise-2 with Solution

From the following table, write a SQL query to find the number of orders booked for each day. Return the result in a format like "For 2001-10-10 there are 15 orders".

*Sample table*: orders

**Sample Solution:**

```
SELECT ' For',ord_date,',there are',
COUNT (ord_no),'orders.'
FROM orders
GROUP BY ord_date;
```

**Output of the Query:**

?column? ord_date ?column? count ?column? For 2012-04-25 ,there are 1 orders. For 2012-06-27 ,there are 1 orders. For 2012-07-27 ,there are 1 orders. For 2012-08-17 ,there are 2 orders. For 2012-09-10 ,there are 3 orders. For 2012-10-05 ,there are 2 orders. For 2012-10-10 ,there are 2 orders.

**Relational Algebra Expression:**

**Relational Algebra Tree:**

**Explanation :**

**Pictorial presentation :**

## Practice Online

## Query Visualization:

**Duration:**

**Rows:**

**Cost:**

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**Previous SQL Exercise:** Salesmen commission with the percent sign (%).

**Next SQL Exercise:** Display orders after sorting orders by order number.

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## SQL: Tips of the Day

**MySQL Like multiple values**

The (a,b,c) list only works with in. For like, you have to use or:

WHERE interests LIKE '%sports%' OR interests LIKE '%pub%'

Ref: https://bit.ly/3CIZPB5

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