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SQL Exercise: Salesmen and customer, who belongs to same city

SQL JOINS: Exercise-1 with Solution

From the following tables write a SQL query to find the salesperson and customer who reside in the same city. Return Salesman, cust_name and city.

Sample table: salesman


Sample table: customer


Sample Solution:

SELECT salesman.name AS "Salesman",
customer.cust_name, customer.city 
FROM salesman,customer 
WHERE salesman.city=customer.city;

Output of the Query:

Salesman	cust_name	city
James Hoog	Nick Rimando	New York
James Hoog	Brad Davis	New York
Pit Alex	Julian Green	London
Mc Lyon		Fabian Johnson	Paris
Nail Knite	Fabian Johnson	Paris
Pit Alex	Brad Guzan	London

Explanation:

The said SQL query is selecting the name of the salesman, the customer's name, and the customer's city from the salesman and customer tables, and only displaying results where the city of the salesman matches the city of the customer. The column "name" of the "salesman" table is given an alias of "Salesman".

Visual Explanation:

Result of prepare a list with salesman name, customer name and their cities for the salesmen and customer who belongs to same city

Practice Online


Query Visualization:

Duration:

Query visualization of Find the salesmen and customers with their name and cities, who belongs to the same city - Duration

Rows:

Query visualization of Find the salesmen and customers with their name and cities, who belongs to the same city - Rows

Cost:

Query visualization of Find the salesmen and customers with their name and cities, who belongs to the same city - Cost

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

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