SQL Exercise: Salesmen and customer, who belongs to same city
SQL JOINS: Exercise-1 with Solution
From the following tables write a SQL query to find the salesperson and customer who reside in the same city. Return Salesman, cust_name and city.
Sample table: salesman
Sample table: customer
SELECT salesman.name AS "Salesman", customer.cust_name, customer.city FROM salesman,customer WHERE salesman.city=customer.city;
Output of the Query:
Salesman cust_name city James Hoog Nick Rimando New York James Hoog Brad Davis New York Pit Alex Julian Green London Mc Lyon Fabian Johnson Paris Nail Knite Fabian Johnson Paris Pit Alex Brad Guzan London
The said SQL query is selecting the name of the salesman, the customer's name, and the customer's city from the salesman and customer tables, and only displaying results where the city of the salesman matches the city of the customer. The column "name" of the "salesman" table is given an alias of "Salesman".
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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