SQL Exercise: Customers and their cities for given range of orders
SQL JOINS: Exercise-2 with Solution
From the following tables write a SQL query to find those orders where the order amount exists between 500 and 2000. Return ord_no, purch_amt, cust_name, city.
Sample table: orders
Sample table: customer
Sample Solution:
SELECT a.ord_no,a.purch_amt,
b.cust_name,b.city
FROM orders a,customer b
WHERE a.customer_id=b.customer_id
AND a.purch_amt BETWEEN 500 AND 2000;
Output of the Query:
ord_no purch_amt cust_name city 70007 948.50 Graham Zusi California 70010 1983.43 Fabian Johnson Paris
Explanation:
The said SQL query is selecting the order number, purchase amount, customer name and customer city from the "orders" table as alias a and "customer" table as alias b, and only displaying results where the customer ID of the "orders" table matches the customer ID of the "customer" table and the purchase amount is between 500 and 2000.
Relational Algebra Expression:

Relational Algebra Tree:

Explanation:

Visual Explanation:

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Previous SQL Exercise: Salesmen and customer, who belongs to same city.
Next SQL Exercise: A list of which salesmen work for which customers.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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