﻿ SQL: Customers and their cities for given range of orders

# SQL Exercise: Customers and their cities for given range of orders

## SQL JOINS: Exercise-2 with Solution

From the following tables write a SQL query to find those orders where the order amount exists between 500 and 2000. Return ord_no, purch_amt, cust_name, city.

Sample table: customer

``` customer_id |   cust_name    |    city    | grade | salesman_id
-------------+----------------+------------+-------+-------------
3002 | Nick Rimando   | New York   |   100 |        5001
3007 | Brad Davis     | New York   |   200 |        5001
3005 | Graham Zusi    | California |   200 |        5002
3008 | Julian Green   | London     |   300 |        5002
3004 | Fabian Johnson | Paris      |   300 |        5006
3009 | Geoff Cameron  | Berlin     |   100 |        5003
3003 | Jozy Altidor   | Moscow     |   200 |        5007
3001 | Brad Guzan     | London     |       |        5005
```

Sample table: orders

```ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001
```

Sample Solution:

``````-- Selecting specific columns from the 'orders' and 'customer' tables
SELECT  a.ord_no, a.purch_amt,
b.cust_name, b.city
-- Specifying the tables to retrieve data from ('orders' as 'a' and 'customer' as 'b')
FROM orders a, customer b
-- Specifying the condition for joining the tables based on customer_id
WHERE a.customer_id = b.customer_id
-- Filtering the results based on the purchase amount between 500 and 2000
AND a.purch_amt BETWEEN 500 AND 2000;
``````

Output of the Query:

```ord_no	purch_amt	cust_name	city
70007	948.50		Graham Zusi	California
70010	1983.43		Fabian Johnson	Paris
```

Explanation:

The said SQL query is selecting the order number, purchase amount, customer name and customer city from the "orders" table as alias a and "customer" table as alias b, and only displaying results where the customer ID of the "orders" table matches the customer ID of the "customer" table and the purchase amount is between 500 and 2000.

Relational Algebra Expression:

Relational Algebra Tree:

Explanation:

Visual Explanation:

## Query Visualization:

Duration:

Rows:

Cost:

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Previous SQL Exercise: Salesmen and customer, who belongs to same city.
Next SQL Exercise: A list of which salesmen work for which customers.

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