SQL Exercise: Display the item name, price, and company name
SQL JOINS: Exercise-22 with Solution
Write a SQL query to display the item name, price, and company name of all the products.
Sample table: company_mast
Sample table: item_mast
SELECT item_mast.pro_name, pro_price, company_mast.com_name FROM item_mast INNER JOIN company_mast ON item_mast.pro_com = company_mast.com_id;
Output of the Query:
pro_name pro_price com_name Mother Board 3200.00 Asus Key Board 450.00 Frontech ZIP drive 250.00 Zebronics Speaker 550.00 Frontech Monitor 5000.00 Samsung DVD drive 900.00 iBall CD drive 800.00 iBall Printer 2600.00 Epsion Refill cartridge 350.00 Epsion Mouse 250.00 iBall
The said SQL query that retrieves specific columns from the table item_mast and company_mast and the INNER JOIN clause to combine the data based on the join condition specified in the ON clause.
The selected columns are 'pro_name' from item_mast, 'pro_price' from item_mast and 'com_name' from company_mast. The join condition is that the 'pro_com' column in the item_mast table matches the 'com_id' column in the 'company_mast' table.
The result of the query is a new table that contains the specified columns from both item_mast and company_mast, with rows that have matching values in the specified columns.
Relational Algebra Expression:
Relational Algebra Tree:
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Previous SQL Exercise: Display each item producer company.
Next SQL Exercise: Display the average price of items of each company.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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