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SQL Exercise: Display ID and price of most expensive product

SQL JOINS: Exercise-25 with Solution

From the following tables write a SQL query to find the most expensive product of each company. Return pro_name, pro_price and com_name.

Sample table: company_mast


Sample table: item_mast


Sample Solution:

SELECT A.pro_name, A.pro_price, F.com_name
   FROM item_mast A INNER JOIN company_mast F
   ON A.pro_com = F.com_id
     AND A.pro_price =
     (
       SELECT MAX(A.pro_price)
         FROM item_mast A
         WHERE A.pro_com = F.com_id
     );

Output of the Query:

pro_name	pro_price	com_name
Monitor		5000.00		Samsung
DVD drive	900.00		iBall
Printer		2600.00		Epsion
ZIP drive	250.00		Zebronics
Mother Board	3200.00		Asus
Speaker		550.00		Frontech

Explanation:

The said SQL query is selecting the product name (A.pro_name), product price (A.pro_price) and the company name (F.com_name) of an item, by joining the item_mast table A and company_mast table F on the pro_com column of the item_mast table and the com_id column of the company_mast table. It is also using a subquery to find the highest price of item of the same company, and then join it with the outer query to show the product name, product price, and the company name that has the highest price.

Practice Online


Query Visualization:

Duration:

Query visualization of Display the name of each company along with the ID and price for their most expensive product - Duration

Rows:

Query visualization of Display the name of each company along with the ID and price for their most expensive product - Rows

Cost:

Query visualization of Display the name of each company along with the ID and price for their most expensive product - Cost

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Previous SQL Exercise: Company whose products have an average price.
Next SQL Exercise: Display employees including their department.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

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