SQL Exercise: Display employees including their department
SQL JOINS: Exercise-26 with Solution
From the following tables write a SQL query to display all the data of employees including their department.
Sample table: emp_details
SELECT emp_idno, A.emp_fname AS "First Name", emp_lname AS "Last Name", B.dpt_name AS "Department", emp_dept, dpt_code, dpt_allotment FROM emp_details A INNER JOIN emp_department B ON A.emp_dept = B.dpt_code;
Output of the Query:
emp_idno First Name Last Name Department emp_dept dpt_code dpt_allotment 631548 Alan Snappy RD 27 27 55000 839139 Maria Foster IT 57 57 65000 127323 Michale Robbin IT 57 57 65000 526689 Carlos Snares Finance 63 63 15000 843795 Enric Dosio IT 57 57 65000 328717 Jhon Snares Finance 63 63 15000 444527 Joseph Dosni HR 47 47 240000 659831 Zanifer Emily HR 47 47 240000 847674 Kuleswar Sitaraman IT 57 57 65000 748681 Henrey Gabriel HR 47 47 240000 555935 Alex Manuel IT 57 57 65000 539569 George Mardy RD 27 27 55000 733843 Mario Saule Finance 63 63 15000
The said SQL query is selecting the employee ID (emp_idno), first name (A.emp_fname) with an alias 'First Name', last name (emp_lname) with an alias 'Last Name', department name (B.dpt_name) with an alias 'Department', emp_dept and department code (dpt_code) and department allotment (dpt_allotment) by joining the emp_details table A and emp_department table B on the emp_dept column of the emp_details table and the dpt_code column of the emp_department table. The query is joining the two tables together and displaying the selected columns from both tables.
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: Display ID and price of most expensive product.
Next SQL Exercise: Employee and sanction amount for their department.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook