SQL Exercise: Employee and sanction amount for their department
SQL JOINS: Exercise-27 with Solution
From the following tables write a SQL query to display the first and last names of each employee, as well as the department name and sanction amount.
Sample table: emp_details
SELECT emp_details.emp_fname AS "First Name", emp_lname AS "Last Name", emp_department.dpt_name AS "Department", dpt_allotment AS "Amount Allotted" FROM emp_details INNER JOIN emp_department ON emp_details.emp_dept = emp_department.dpt_code;
Output of the Query:
First Name Last Name Department Amount Allotted Alan Snappy RD 55000 Maria Foster IT 65000 Michale Robbin IT 65000 Carlos Snares Finance 15000 Enric Dosio IT 65000 Jhon Snares Finance 15000 Joseph Dosni HR 240000 Zanifer Emily HR 240000 Kuleswar Sitaraman IT 65000 Henrey Gabriel HR 240000 Alex Manuel IT 65000 George Mardy RD 55000 Mario Saule Finance 15000
The said SQL query is selecting the employee's first name (emp_details.emp_fname) with an alias 'First Name', last name (emp_lname) with an alias 'Last Name', department name (emp_department.dpt_name) with an alias 'Department', and department allotment (dpt_allotment) with an alias 'Amount Allotted' by joining the emp_details table and emp_department table on the emp_dept column of the emp_details table and the dpt_code column of the emp_department table. The query is joining the two tables together and displaying the selected columns from both tables.
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Previous SQL Exercise: Display employees including their department.
Next SQL Exercise: Find employees and departments with a given budget.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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