SQL Exercises: Find out customers who made the order
SQL Query on Multiple Tables: Exercise-4 with Solution
From the following tables, write a SQL query to locate the orders made by customers. Return order number, customer name.
Sample table: orders
Sample table: customer
Sample Solution:
SELECT orders.ord_no, customer.cust_name
FROM orders, customer
WHERE orders.customer_id = customer.customer_id;
Output of the query:
ord_no cust_name 70009 Brad Guzan 70002 Nick Rimando 70004 Geoff Cameron 70005 Brad Davis 70008 Nick Rimando 70010 Fabian Johnson 70003 Geoff Cameron 70011 Jozy Altidor 70013 Nick Rimando 70001 Graham Zusi 70007 Graham Zusi 70012 Julian Green
Code Explanation:
The said query in SQL that joins the orders' and 'customer' tables based on the "customer_id" column. The result set includes the order number (ord_no) and customer name (cust_name). The WHERE clause specifies the join condition between the two tables, which is that the "customer_id" column must be equal in both tables.
Relational Algebra Expression:

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Visual presentation :

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Previous SQL Exercise: Customer lives in a city other than the salesman's.
Next SQL Exercise: Sort out the customer who made at least an order.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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