SQL Exercises: Largest and smallest orders on each date

Last update on December 20 2024 12:05:10 (UTC/GMT +8 hours)

5. From the following tables, write a SQL query to find the salespeople who generated the largest and smallest orders on each date. Sort the result-set on third field. Return salesperson ID, name, order no., highest on/lowest on, order date.

Sample table: Salesman

Sample table: Orders

Sample Solution:

-- Selecting specific columns (a.salesman_id, name, ord_no, 'highest on', ord_date) from the 'salesman' table (aliased as 'a') and the 'orders' table (aliased as 'b')
SELECT a.salesman_id, name, ord_no, 'highest on', ord_date

-- Joining the 'salesman' table (aliased as 'a') and the 'orders' table (aliased as 'b') based on the condition that 'salesman_id' is equal in both tables and filtering rows based on the condition that 'purch_amt' is equal to the maximum 'purch_amt' for the same 'ord_date'
FROM salesman a, orders b
WHERE a.salesman_id = b.salesman_id
AND b.purch_amt = (
    SELECT MAX(purch_amt)
    FROM orders c
    WHERE c.ord_date = b.ord_date
)

-- Performing a UNION operation with the result set of a subquery that selects specific columns (a.salesman_id, name, ord_no, 'lowest on', ord_date) from the 'salesman' table (aliased as 'a') and the 'orders' table (aliased as 'b')
UNION

-- Selecting specific columns (a.salesman_id, name, ord_no, 'lowest on', ord_date) from the 'salesman' table (aliased as 'a') and the 'orders' table (aliased as 'b')
SELECT a.salesman_id, name, ord_no, 'lowest on', ord_date

-- Joining the 'salesman' table (aliased as 'a') and the 'orders' table (aliased as 'b') based on the condition that 'salesman_id' is equal in both tables and filtering rows based on the condition that 'purch_amt' is equal to the minimum 'purch_amt' for the same 'ord_date'
FROM salesman a, orders b
WHERE a.salesman_id = b.salesman_id
AND b.purch_amt = (
    SELECT MIN(purch_amt)
    FROM orders c
    WHERE c.ord_date = b.ord_date
)

-- Ordering the result set based on the third column (ord_no)
ORDER BY 3

Sample Output:

salesman_id	name		ord_no	?column?	ord_date
5002		Nail Knite	70001	highest on	2012-10-05
5001		James Hoog	70002	lowest on	2012-10-05
5003		Lauson Hen	70003	highest on	2012-10-10
5003		Lauson Hen	70004	highest on	2012-08-17
5001		James Hoog	70005	lowest on	2012-07-27
5001		James Hoog	70005	highest on	2012-07-27
5001		James Hoog	70008	highest on	2012-09-10
5005		Pit Alex	70009	lowest on	2012-09-10
5006		Mc Lyon		70010	lowest on	2012-10-10
5007		Paul Adam	70011	lowest on	2012-08-17
5002		Nail Knite	70012	lowest on	2012-06-27
5002		Nail Knite	70012	highest on	2012-06-27
5001		James Hoog	70013	lowest on	2012-04-25
5001		James Hoog	70013	highest on	2012-04-25

Code Explanation:

The said query in SQL that retrieves information about the highest and lowest orders placed by each salesman, along with the date of the order.
The first query before UNION keyword selects the salesman ID, name, order number, and order date for the highest order placed by each salesman. It does so by joining the 'salesman' and 'orders' tables and selecting rows where the salesman ID matches in both tables, and the purchase amount is equal to the maximum purchase amount for that date, as determined by a subquery.
The second query after UNION keyword selects the lowest order for each salesman.
The "UNION" keyword combines the results of the two queries into a single table.
The ORDER BY clause orders the results by the third column, which is the order number.

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