C Exercises: Check whether it is possible to add two integers to get the third integer from three given integers

C-programming basic algorithm: Exercise-23 with Solution

Write a C program to check whether it is possible to add two integers to get the third integer from three given integers.

C Code:

#include <stdio.h> // Include standard input/output library
#include <stdlib.h> // Include standard library for additional functions

// Function declaration for 'test' with three integer parameters 'x', 'y', and 'z'
int test(int x, int y, int z);

int main(void){
    // Print the result of calling 'test' with different integer values and format the output
    printf("%d",test(1, 2, 3));
    printf("\n%d",test(4, 5, 6));
    printf("\n%d",test(-1, 1, 0));
}

// Function definition for 'test'
int test(int x, int y, int z)
{
    // Check if any two numbers among 'x', 'y', and 'z' add up to the third number
    if (x == y + z || y == x + z || z == x + y) {
        return 1; // If the condition is true, return 1
    } else {
        return 0; // If the condition is false, return 0
    }
}

Sample Output:

1
0
1

Explanation:

int test(int x, int y, int z) {
  return x == y + z || y == x + z || z == x + y;
}

The function takes three integers x, y, and z as input and checks if any two of them add up to the third one. It returns 1 if the condition is true, otherwise, it returns 0.

Time complexity and space complexity:

The time complexity of the given function is O(n) as it performs a fixed number of operations irrespective of the size of the inputs.

Space complexity: O(1)
The space complexity of the given function is O(1) as the function uses a fixed amount of memory to store the input variables and the return value. Therefore, the space complexity is constant.

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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