C Exercises: Check a given array of integers and return true if the array contains three increasing adjacent numbers

C-programming basic algorithm: Exercise-67 with Solution

Write a C program to check a given array of integers and return true if the array contains three increasing adjacent numbers.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int numbers[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 2, 3, 5, 3, 7};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {3, 7, 5, 5, 3, 7 };
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = { 3, 7, 5, 5, 6, 7, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));
}

// Definition of the 'test' function
int test(int numbers[], int arr_size)
{
    // Looping through the array until the third-to-last element
    for (int i = 0; i <= arr_size - 3; i++)
    {
        // Checking if consecutive elements are in an increasing sequence
        if (numbers[i] == numbers[i + 1] - 1
&& numbers[i] == numbers[i + 2] - 2)
        {
            return 1; // Return 1 if the condition is met
        }
    }

    return 0; // Return 0 if the condition is not met
}

Sample Output:

1
0
1

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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