﻿ C Program: Shift all zeros to the left in a given array

# C Exercises: Create a new array from a given array of integers shifting all zeros to left direction

## C-programming basic algorithm: Exercise-71 with Solution

Write a C program to create a new array from a given array of integers shifting all zeros to left direction.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'print_array'
void print_array(int parray[], int size);

int main(void){
int arr_size;

// Declaration and initialization of an integer array 'a1'
int a1[] = {1, 2, 0, 3, 5, 7, 0, 9, 11};
arr_size = sizeof(a1)/sizeof(a1);

// Printing the elements of the original array 'a1'
printf("Elements in original array are: ");
print_array(a1, arr_size);

// Declaration of 'pos' variable to keep track of position of 0 in 'a1'
int pos = 0;

// Loop to iterate through the elements of 'a1'
for (int i = 0; i < arr_size; i++)
{
// If the current element is 0, swap it with the element at 'pos' and increment 'pos'
if (a1[i] == 0)
{
a1[i] = a1[pos];
a1[pos++] = 0;
}
}

// Update 'arr_size' to reflect the size of the modified 'a1' array
arr_size = sizeof(a1)/sizeof(a1);

// Printing the elements of the modified array 'a1'
printf("\nElements in new array are: ");
print_array(a1, arr_size);
}

// Definition of the 'print_array' function
void print_array(int parray[], int size)
{
int i;
// Loop to print the elements of the array
for( i = 0; i < size - 1; i++)
{
printf("%d, ", parray[i]);
}
// Printing the last element
printf("%d ", parray[i]);
printf("\n");
}
``````

Sample Output:

```Elements in original array are: 1, 2, 0, 3, 5, 7, 0, 9, 11

Elements in new array are: 0, 0, 1, 3, 5, 7, 2, 9, 11
```

Pictorial Presentation: Flowchart: C Programming Code Editor:

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