C Exercises: Create a new array from a given array of integers shifting all zeros to left direction

C-programming basic algorithm: Exercise-71 with Solution

Write a C program to create a new array from a given array of integers shifting all zeros to left direction.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'print_array'
void print_array(int parray[], int size);

int main(void){ 
    int arr_size;

    // Declaration and initialization of an integer array 'a1'
    int a1[] = {1, 2, 0, 3, 5, 7, 0, 9, 11};
    arr_size = sizeof(a1)/sizeof(a1[0]);

    // Printing the elements of the original array 'a1'
    printf("Elements in original array are: ");  
    print_array(a1, arr_size);

    // Declaration of 'pos' variable to keep track of position of 0 in 'a1'
    int pos = 0;

    // Loop to iterate through the elements of 'a1'
    for (int i = 0; i < arr_size; i++)
    {
        // If the current element is 0, swap it with the element at 'pos' and increment 'pos'
        if (a1[i] == 0)
        {
            a1[i] = a1[pos];
            a1[pos++] = 0;
        }
    }

    // Update 'arr_size' to reflect the size of the modified 'a1' array
    arr_size = sizeof(a1)/sizeof(a1[0]);                

    // Printing the elements of the modified array 'a1'
    printf("\nElements in new array are: ");  
    print_array(a1, arr_size);
}      

// Definition of the 'print_array' function
void print_array(int parray[], int size)
{
    int i;      
    // Loop to print the elements of the array
    for( i = 0; i < size - 1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
    // Printing the last element
    printf("%d ", parray[i]);  
    printf("\n");   
}

Sample Output:

Elements in original array are: 1, 2, 0, 3, 5, 7, 0, 9, 11 

Elements in new array are: 0, 0, 1, 3, 5, 7, 2, 9, 11

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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