# C Exercises: Sum of n even numbers starting from m

## C Basic Declarations and Expressions: Exercise-122 with Solution

Write a C program that reads two integers m, n and computes the sum of n even numbers starting from m.

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
int main () {
int m, n, i, j, k, sum_even_nums = 0;
// Prompt user for input
printf("\nInput two integers (m, n):\n");
// Read two integer values 'm' and 'n' from user
scanf("%d %d", &m, &n);
// Print a message indicating what the program will do
printf("\nSum of %d even numbers starting from %d: ",n,m);
// Loop to find and sum 'n' even numbers starting from 'm'
for (k = 0, j = m; k < n; j++) {
// Check if 'j' is even
if (j % 2 == 0) {
sum_even_nums += j; // Accumulate even numbers
k++; // Increment the count of even numbers found
}
}
// Print the sum of even numbers
printf("\n%d", sum_even_nums);
return 0; // End of program
}
```

Sample Output:

Input two integes (m, n): 20 60 Sum of 60 even numbers starting from 20: 4740

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