C Exercises: Replace every negative or null element of an array by 1 and print the array elements

Last update on September 19 2025 12:45:14 (UTC/GMT +8 hours)

Replace negative/null elements of an array with 1

Write a C program that reads an array of integers (length 7), replaces every negative or null element with 1 and prints the array elements.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
    int array_nums[7], i, n;

    // Prompt user for input
    printf("Input 7 array elements:\n");

    // Loop to read 7 integer values from the user and store them in the array
    for (i = 0; i < 7; i++) {
        scanf("%d", &n);
        array_nums[i] = n;
    }

    // Print a message indicating the array elements will be displayed
    printf("\nArray elements:\n");

    // Loop to print each element of the array
    for (i = 0; i < 7; i++) {

        // Check if the element is less than or equal to 0
        if (array_nums[i] <= 0) {
            array_nums[i] = 1; // Set the element to 1 if it's less than or equal to 0
        }

        // Print the array element and its value
        printf("array_nums[%d] = %d\n", i, array_nums[i]);
    }

    return 0; // End of program
}

Sample Output:

Input 7 array elements:
15
12
-7
25
0
27
53

Array elements:
array_nums[0] = 15
array_nums[1] = 12
array_nums[2] = 1
array_nums[3] = 25
array_nums[4] = 1
array_nums[5] = 27
array_nums[6] = 53

Flowchart:

C Programming Flowchart: Replace every negative or null element of an array by 1 and print the array elements.

For more Practice: Solve these Related Problems:

Write a C program to iterate through an array and replace every non-positive element with 1 using pointer arithmetic.
Write a C program to use a loop and conditional statements to substitute negative and zero values in an array with 1.
Write a C program to modify an array by scanning each element and replacing invalid (<=0) numbers with 1.
Write a C program to dynamically allocate an array, check each element, and replace negatives or zeros with 1 before printing.

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