C Exercises: Select specific array values

C Basic Declarations and Expressions: Exercise-126 with Solution

Write a C program that reads an array (length 7) and prints all array positions that store a value less than or equal to 0.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
    float n, array_nums[7];
    int i;

    // Prompt user for input
    printf("Input 7 array elements:\n");

    // Loop to read 7 float values from the user and store them in the array
    for (i = 0; i < 7; i++) {
        scanf("%f", &n);
        array_nums[i] = n;
    }

    // Print a message indicating the positions with values less than or equal to 0
    printf("\nArray positions that store a value less or equal to 0:\n");

    // Loop to check and print positions with values less than or equal to 0
    for (i = 0; i < 7; i++) {
        if (array_nums[i] <= 0) {
            printf("array_nums[%d] = %.1f\n", i, array_nums[i]);
        }
    }

    return 0; // End of program
}

Sample Output:

Input 7 array elements:
15
23
37
65
20
-7
65

Array positions that store a value less or equal to 0:
array_nums[5] = -7.0

Flowchart:

C programming Code Editor:

Previous: Write a C program that reads an array of integers (length 7), and replace the first element of the array by a give number and replace each subsequent position of the array by the double value of the previous.
Next: Write a C program that reads an array of integers (length 8), replace the 1st element by the 8^th, 2^nd by the 7^th and so on. Print the final array.