C Exercises: Display the first n terms of Fibonacci series
C For Loop: Exercise-35 with Solution
Write a program in C to display the first n terms of Fibonacci series. The series is as follows:
Fibonacci series 0 1 2 3 5 8 13 .....
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int prv=0,pre=1,trm,i,n;
printf("Input number of terms to display : ");
scanf("%d",&n);
printf("Here is the Fibonacci series upto to %d terms : \n",n);
printf("% 5d % 5d", prv,pre);
for(i=3;i<=n;i++)
{
trm=prv+pre;
printf("% 5d",trm);
prv=pre;
pre=trm;
}
printf("\n");
}
Sample Output:
Input number of terms to display : 10 Here is the Fibonacci series upto to 10 terms : 0 1 1 2 3 5 8 13 21 34
Flowchart:

C Programming Code Editor:
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Previous: Write a program in C to find the prime numbers within a range of numbers.
Next: Write a program in C to display the such a pattern for n number of rows using a number which will start with the number 1 and the first and a last number of each row will be 1.
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C Programming: Tips of the Day
Is there a way to specify how many characters of a string to print out using printf()?
The basic way is:
printf ("Here are the first 8 chars: %.8s\n", "A string that is more than 8 chars");
The other, often more useful, way is:
printf ("Here are the first %d chars: %.*s\n", 8, 8, "A string that is more than 8 chars");
Here, you specify the length as an int argument to printf(), which treats the '*' in the format as a request to get the length from an argument.
You can also use the notation:
printf ("Here are the first 8 chars: %*.*s\n", 8, 8, "A string that is more than 8 chars");
This is also analogous to the "%8.8s" notation, but again allows you to specify the minimum and maximum lengths at runtime - more realistically in a scenario like:
printf("Data: %*.*s Other info: %d\n", minlen, maxlen, string, info);
The POSIX specification for printf() defines these mechanism
Ref : https://bit.ly/3u32GyO
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