C Exercises: Convert a binary to a decimal using for loop and without using array
C For Loop: Exercise-42 with Solution
Write a program in C to convert a binary number into a decimal number without using array, function and while loop.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
void main()
{ int n1, n,p=1;
int dec=0,i=1,j,d;
printf("\n\n Convert Binary to Decimal:\n ");
printf("-------------------------\n");
printf("Input a binary number :");
scanf("%d",&n);
n1=n;
for (j=n;j>0;j=j/10)
{
d = j % 10;
if(i==1)
p=p*1;
else
p=p*2;
dec=dec+(d*p);
i++;
}
printf("\nThe Binary Number : %d\nThe equivalent Decimal Number : %d \n\n",n1,dec);
}
Sample Output:
Convert Binary to Decimal: ------------------------- Input a binary number :11001 The Binary Number : 11001 The equivalent Decimal Number : 25
Flowchart:

C Programming Code Editor:
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Previous: Write a program in C to convert a decimal number into binary without using an array.
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C Programming: Tips of the Day
Printing hexadecimal characters in C:
You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.
Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.
char int c0 -> ffffffc0 80 -> ffffff80 61 -> 00000061Here's a solution:
char ch = 0xC0; printf("%x", ch & 0xff);
This will mask out the upper bits and keep only the lower 8 bits that you want.
Ref : https://bit.ly/3vOLizM
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