# C Exercises: Find the square root of a number using Babylonian method

## C Programming Mathematics: Exercise-19 with Solution

Write a C program to find the square root of a number using the Babylonian method.

Example 1:

Input: n = 50

Output: 7.071068

Example 2:

Input: n = 17

Output: 4.123106

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
float square_Root(float n)
{
float a = n;
float b = 1;
double e = 0.000001;
while (a - b > e) {
a = (a + b) / 2;
b = n / a;
}
return a;
}
int main(void)
{
int n = 50;
printf("Square root of %d is %f", n, square_Root(n));
n = 17;
printf("\nSquare root of %d is %f", n, square_Root(n));
return 0;
}
```

Sample Output:

Square root of 50 is 7.071068 Square root of 17 is 4.123106

**Flowchart: **

**C Programming Code Editor:**

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