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C Exercises: Remove all instances of a given value in a given array of integers and return the length of the new array

C Programming Practice: Exercise-13 with Solution

Write a C programming to remove all instances of a given value in a given array of integers and return the length of the new array.

C Code:

#include <stdio.h>
#include <stdlib.h>

static int removeElement(int *nums, int arr_size, int val)
{
    int i, ctr = 0;
    for (i = 0; i < arr_size; i++) {
        if (nums[i] != val) {
            nums[ctr++] = nums[i];
        }
    }
    return ctr;
}

int main(void)
{
    int nums[] = {1,1,2,3,4,4,5,6,6,6};    
    int size = sizeof(nums)/sizeof(nums[0]);
    printf("Original array:\n");
    int i;
	int val = 4;
    for (i = 0; i < size; i++) {
        printf("%d ", nums[i]);
    }
    int new_size = removeElement(nums, size, val);
    printf("\nSize of the new array after removing the value 4: %d\n",new_size);
    return 0;
}

Sample Output:

Original array:
1 1 2 3 4 4 5 6 6 6 
Size of the new array after removing the value 4: 8

Pictorial Presentation:

C Programming: Remove all instances of a given value in a given array of integers and return the length of the new array.

Flowchart:

C Programming Flowchart: Remove all instances of a given value in a given array of integers and return the length of the new array

C Programming Code Editor:

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C Programming: Tips of the Day

Maximum value of int:

In C:

#include <limits.h>
then use
int imin = INT_MIN; // minimum value
int imax = INT_MAX;

or

#include <float.h>

float fmin = FLT_MIN;  // minimum positive value
double dmin = DBL_MIN; // minimum positive value

float fmax = FLT_MAX;
double dmax = DBL_MAX;

Ref : https://bit.ly/3fi8yk9