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C modf() function

C modf() function - Floating-point remainder value function

Syntax:

double modf(double x, double *iptr)

The modf() function is used to break down the floating-point value x into fractional and integral parts.

Parameters:

Name Description Required /Optional
x Floating-point values. Required
iptr Floating-point values. Required

Return value from modf()

  • Returns the signed fractional portion of x.

Example: modf() function

The following example shows the usage of modf() function.


#include <math.h>
#include <stdio.h>
 
int main(void)
{
   double x, y, d;
 
   x = -14.876;
   y = modf(x, &d);
 
   printf("x = %lf\n", x);
   printf("Integral part = %lf\n", d);
   printf("Fractional part = %lf\n", y);
   x = 7654.887;
   y = modf(x, &d);
 
   printf("\nx = %lf\n", x);
   printf("Integral part = %lf\n", d);
   printf("Fractional part = %lf\n", y);
}

Output:

x = -14.876000
Integral part = -14.000000
Fractional part = -0.876000

x = 7654.887000
Integral part = 7654.000000
Fractional part = 0.887000

C Programming Code Editor:

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C Programming: Tips of the Day

What's the point of const pointers?

const is a tool which you should use in pursuit of a very important C++ concept:

Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.

Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:

void foo(int* ptr)
{
    ptr = 0;// oops, I meant *ptr = 0
}

If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.

Ref : https://bit.ly/33Cdn3Q