C++ Exercises: Check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array

C++ Basic Algorithm: Exercise-114 with Solution

Check if Specified Elements Appear at Both Start and End of Array

Write a C++ program to check a given array of integers. The program will return true if the specified number of the same elements appears at the start and end of the given array.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function to check if the last 'n' elements in the array match the first 'n' elements
static bool test(int numbers[], int arr_length, int n)
{
    // Loop through the first 'n' elements and compare with the last 'n' elements
    for (int i = 0; i < n; i++)
    {
        // Check for inequality between elements from the beginning and end of the array
        if (numbers[i] != numbers[arr_length - n + i])
        {
            return false;  // Return false if inequality is found
        }
    }

    return true;  // Return true if all 'n' elements match between the two segments
}   

// Main function
int main() 
{  
    // Different test cases with arrays of integers and 'n' value
    int nums1[] = {3, 7, 5, 5, 3, 7 };  // Last 2 elements match the first 2 elements
    int n = 2;
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length, n) << endl; 

    int nums2[] = {3, 7, 5, 5, 3, 7};  // Last 3 elements do not match the first 3 elements
    n = 3;
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length, n) << endl;

    int nums3[] = {3, 7, 5, 5, 3, 7, 5};  // Last 3 elements match the first 3 elements
    n = 3;
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length, n) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

1
0
1

Visual Presentation:

Flowchart:

C++ Code Editor:

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