C++ Exercises: New array from an existing array

Last update on January 12 2023 13:04:06 (UTC/GMT +8 hours)

C++ Basic Algorithm: Exercise-120 with Solution

Write a C++ program to create a new array using the first n strings from a given array of strings. (n>=1 and <=length of the array).

Test Data:
({"a", "b", "bb", "c", "ccc" }, 2) -> {"a", "b"}
({"a", "b", "bb", "c", "ccc" }, 3) -> {"a", "b", "bb"}

Sample Solution:

C++ Code :

#include <iostream>

#include<string.h>

using namespace std;
string *new_array;
string *test(string *text, int n)
{
     new_array = new string[n];
     for(int i = 0; i < n; i++)
    {
         new_array[i] = text[i] ;
           }
           return new_array;
}
int main(){
     string text [] = {"a","b","bb","c","ccc"};
     string* result_array;
   int arr_length = sizeof(text) / sizeof(text[0]);
   cout << "Original array elements: " << endl;
   for (int i = 0; i < arr_length; i++)
     {
      std::cout << text[i] << ' ';
     }
   int n = 2;
     result_array = test(text, n);
     cout << "\n\nNew array with size "<< n << endl;
     for(int i = 0; i < n; i++)
      {
      std::cout << result_array[i] << ' ';
      }
     n = 4;
     result_array = test(text, n);
     cout << "\n\nNew array with size "<< n << endl;
     for(int i = 0; i < n; i++)
      {
      std::cout << result_array[i] << ' ';
      }
   delete [] new_array;
     return 0;
}

Sample Output:

Original array elements: 
a b bb c ccc 

New array with size 2
a b 

New array with size 4
a b bb c

Flowchart:

C++ Code Editor:

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Next: Array from an existing array using string length.

What is the difficulty level of this exercise?

C++ Programming: Tips of the Day

What is the usefulness of `enable_shared_from_this?

It enables you to get a valid shared_ptr instance to this, when all you have is this. Without it, you would have no way of getting a shared_ptr to this, unless you already had one as a member.

class Y: public enable_shared_from_this
{
public:

    shared_ptr f()
    {
        return shared_from_this();
    }
}

int main()
{
    shared_ptr p(new Y);
    shared_ptr q = p->f();
    assert(p == q);
    assert(!(p < q || q < p)); // p and q must share ownership
}

The method f() returns a valid shared_ptr, even though it had no member instance. Note that you cannot simply do this:

class Y: public enable_shared_from_this
{
public:

    shared_ptr f()
    {
        return shared_ptr(this);
    }
}

The shared pointer that this returned will have a different reference count from the "proper" one, and one of them will end up losing and holding a dangling reference when the object is deleted.

Ref : https://bit.ly/3pwVzzz