C++ Exercises: Check three given integers and return true if one of them is 20 or more less than one of the others
C++ Basic Algorithm: Exercise-48 with Solution
Write a C++ program to check three given integers and return true if one of them is 20 lower than one of the others.
Sample Solution:
C++ Code :
#include <iostream>
using namespace std;
bool test(int x, int y, int z)
{
return abs(x - y) >= 20 || abs(x - z) >= 20 ||
abs(y - z) >= 20;
}
int main()
{
cout << test(11, 21, 31) << endl;
cout << test(11, 22, 31) << endl;
cout << test(10, 20, 15) << endl;
return 0;
}
Sample Output:
1 1 0
Pictorial Presentation:

Flowchart:

C++ Code Editor:
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Previous: Write a C++ program to check if two or more non-negative given integers have the same rightmost digit.
Next: Write a C++ program to find the larger from two given integers. However if the two integers have the same remainder when divided by 7, then the return the smaller integer. If the two integers are the same, return 0.
What is the difficulty level of this exercise?
C++ Programming: Tips of the Day
Advantage of switch over if-else statement
Use switch.
In the worst case the compiler will generate the same code as a if-else chain, so you don't lose anything. If in doubt put the most common cases first into the switch statement.
In the best case the optimizer may find a better way to generate the code. Common things a compiler does is to build a binary decision tree (saves compares and jumps in the average case) or simply build a jump-table (works without compares at all).
Ref: https://bit.ly/3G0uBqS
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