﻿ C++ : If one of 3 integers is 20 or more, less than others

# C++ Exercises: Check three given integers and return true if one of them is 20 or more less than one of the others

## C++ Basic Algorithm: Exercise-48 with Solution

Write a C++ program to check three given integers and return true if one of them is 20 lower than one of the others.

Sample Solution:

C++ Code :

``````#include <iostream>
using namespace std;

bool test(int x, int y, int z)
{
return abs(x - y) >= 20 || abs(x - z) >= 20 ||
abs(y - z) >= 20;
}

int main()
{
cout << test(11, 21, 31) << endl;
cout << test(11, 22, 31) << endl;
cout << test(10, 20, 15) << endl;
return 0;
}
``````

Sample Output:

```1
1
0
```

Pictorial Presentation: Flowchart: C++ Code Editor:

What is the difficulty level of this exercise?

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## C++ Programming: Tips of the Day

Advantage of switch over if-else statement

Use switch.

In the worst case the compiler will generate the same code as a if-else chain, so you don't lose anything. If in doubt put the most common cases first into the switch statement.

In the best case the optimizer may find a better way to generate the code. Common things a compiler does is to build a binary decision tree (saves compares and jumps in the average case) or simply build a jump-table (works without compares at all).

Ref: https://bit.ly/3G0uBqS

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