C++ Exercises: Reverse a given array of integers and length 5

C++ Basic Algorithm: Exercise-86 with Solution

Write a C++ program to reverse a given array of integers of length 5.

Sample Solution:

C++ Code :

#include <iostream> // Including the input/output stream library
using namespace std; // Using the standard namespace

// Function that creates and returns a reversed array
int *test(int nums[]) {
   // Static array storing the elements of the input array in reverse order
   static int r_array[] = {nums[4], nums[3], nums[2], nums[1], nums[0] }; 
   return r_array; // Returning the reversed array
}

// Main function
int main () {
   int *p; // Pointer to an integer

   int nums[] = {0, 10, 20, 30, 40}; // Define an array nums
   int arr_length = sizeof(nums) / sizeof(nums[0]); // Calculate the length of nums

   cout << "Original array: " << endl;   
   for ( int i = 0; i < arr_length; i++ ) {    
      cout << nums[i] << " "; // Output the original array
   }

   p = test(nums); // Reverse the array and assign it to pointer p

   cout << "\nReverse array: " << endl;
   for ( int i = 0; i < arr_length; i++ ) {
      cout << *(p + i) << " "; // Output the reversed array
   }

   return 0; // Return statement indicating successful termination of the program
}

Sample Output:

Original array:
0 10 20 30 40
Reverse array:
40 30 20 10 0

Visual Presentation:

Flowchart:

C++ Code Editor:

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