C++ Exercises: Display the number in reverse order

C++ For Loop: Exercise-30 with Solution

Write a program in C++ to display the numbers in reverse order.

Visual Presentation:

Sample Solution:-

C++ Code :

#include <iostream> // Including input-output stream header

using namespace std; // Using standard namespace to avoid writing std::

int main() // Start of the main function
{
    int num, r, sum = 0, t; // Declaration of integer variables: 'num' (input number), 'r' (remainder), 'sum' (stores the reversed number), 't' (temporary variable)

    cout << "\n\n Display the number in reverse order:\n"; // Displaying a message on the console
    cout << "-----------------------------------------\n";
    cout << " Input a number: "; // Asking the user for a number
    cin >> num; // Reading the number from the user

    for (t = num; num != 0; num = num / 10) // Reversing the number using a loop
    {
        r = num % 10; // Getting the rightmost digit of the number
        sum = sum * 10 + r; // Constructing the reversed number by adding digits one by one from the original number
    }

    cout << " The number in reverse order is : " << sum << endl; // Displaying the reversed number
}

Sample Output:

 Display the number in reverse order:                                  
-----------------------------------------                              
 Input a number: 12345                                                 
 The number in reverse order is : 54321  

Flowchart:

C++ Code Editor:

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