# C++ Exercises: Find out the sum of an A.P. series

## C++ For Loop: Exercise-31 with Solution

Write a C++ program to find the sum of an A.P. series.

**Pictorial Presentation:**

**Sample Solution**:-

**C++ Code :**

```
#include <iostream>
using namespace std;
int main()
{
int n1, df, n2, i, ln;
int s1 = 0;
cout << "\n\n Find out the sum of A.P. series:\n";
cout << "-----------------------------------------\n";
cout << " Input the starting number of the A.P. series: ";
cin >> n1;
cout << " Input the number of items for the A.P. series: ";
cin >> n2;
cout << " Input the common difference of A.P. series: ";
cin >> df;
s1 = (n2 * (2 * n1 + (n2 - 1) * df)) / 2;
ln = n1 + (n2 - 1) * df;
cout << " The Sum of the A.P. series are : " << endl;
for (i = n1; i <= ln; i = i + df)
{
if (i != ln)
cout << i << " + ";
else
cout << i << " = " << s1 << endl;
}
}
```

Sample Output:

Find out the sum of A.P. series: ----------------------------------------- Input the starting number of the A.P. series: 1 Input the number of items for the A.P. series: 8 Input the common difference of A.P. series: 5 The Sum of the A.P. series are : 1 + 6 + 11 + 16 + 21 + 26 + 31 + 36 = 148

**Flowchart: **

**C++ Code Editor:**

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