C++ Exercises: Find out the sum of an A.P. series

C++ For Loop: Exercise-31 with Solution

Write a C++ program to find the sum of an A.P. series.

Pictorial Presentation:

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;

int main()
{
    int n1, df, n2, i, ln;
    int s1 = 0;
    cout << "\n\n Find out the sum of A.P. series:\n";
    cout << "-----------------------------------------\n";
    cout << " Input  the starting number of the A.P. series: ";
    cin >> n1;
    cout << " Input the number of items for  the A.P. series: ";
    cin >> n2;
    cout << " Input  the common difference of A.P. series: ";
    cin >> df;
    s1 = (n2 * (2 * n1 + (n2 - 1) * df)) / 2;
    ln = n1 + (n2 - 1) * df;
    cout << " The Sum of the  A.P. series are : " << endl;
    for (i = n1; i <= ln; i = i + df) 
    {
        if (i != ln)
            cout << i << " + ";
        else
            cout << i << " = " << s1 << endl;
    }
}

Sample Output:

 Find out the sum of A.P. series:                                      
-----------------------------------------                              
 Input  the starting number of the A.P. series: 1                      
 Input the number of items for  the A.P. series: 8                     
 Input  the common difference of A.P. series: 5                        
 The Sum of the  A.P. series are :                                     
1 + 6 + 11 + 16 + 21 + 26 + 31 + 36 = 148  

Flowchart:

C++ Code Editor:

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