C++ Exercises: Display specified pattern for n number of rows using number

C++ For Loop: Exercise-55 with Solution

Write a program in C++ to display such a pattern for n number of rows using numbers. There will be odd numbers in each row. The first and last number of each row will be 1 and the middle column will be the row number. N numbers of columns will appear in the 1st row.

 Input number of rows: 7                                                                                      
     1234567654321                                                                                            
      12345654321                                                                                             
       123454321                                                                                              
        1234321                                                                                               
         12321                                                                                                
          121                                                                                                 
           1 

Visual Presentation:

Sample Solution:

C++ Code :

#include <iostream> // Include the input/output stream library
using namespace std; // Using standard namespace

int main() // Main function where the execution of the program starts
{
    int i, j, n; // Declare integer variables i, j, and n

    // Display message asking for input
    cout << "\n\n Display a pattern using odd number of numbers, the n numbers of columns will appear in 1st row:\n";
    cout << "----------------------------------------------------------------------------------------------------\n";
    cout << " Input number of rows: ";
    cin >> n; // Read input for the number of rows from the user

    for (i = n; i <= 1; i--) // Loop for the number of rows in reverse order
    {
        /* print blank spaces based on the row number */
        for (j = 1; j <= n + 5 - i; j++) // Print spaces based on row number for formatting
            cout << " "; // Print spaces

        /* Display numbers in ascending order up to the middle */
        for (j = 1; j <= i; j++) // Loop to print numbers in ascending order
            cout << j; // Print the numbers in ascending order

        /* Display numbers in reverse order after the middle */
        for (j = i - 1; j >= 1; j--) // Loop to print numbers in reverse order after the middle
            cout << j; // Print the numbers in reverse order

        cout << endl; // Move to the next line after each row is printed
    }
}

Sample Output:

 Display a pattern using odd number of numbers, the n numbers of column
s will appear in 1st row:                                              
-----------------------------------------------------------------------
-----------------------------                                          
 Input number of rows: 7                                               
     1234567654321                                                     
      12345654321                                                      
       123454321                                                       
        1234321                                                        
         12321                                                         
          121                                                          
           1

Flowchart:

C++ Code Editor:

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