﻿ C# - New array of length 3 using middle elements of a array

# C#: Create a new array of length 3 from a given array using the elements from the middle of the array

## C# Sharp Basic Algorithm: Exercise-106 with Solution

Write a C# Sharp program to create an array length 3 from a given array (length at least 3) using the elements in the middle of the array.

visual Presentation:

Sample Solution:-

C# Sharp Code:

``````using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
class Program // Defining a class named 'Program'
{
static void Main(string[] args) // The entry point of the program
{
// Calling the 'test' method with an integer array as an argument and assigning the result to the 'item' array
int[] item = test(new[] { 1, 5, 7, 9, 11, 13 });

// Outputting text to indicate the start of displaying the new array
Console.Write("New array: ");

// Looping through each element of the 'item' array and displaying them
foreach(var i in item)
{
Console.Write(i.ToString()+" "); // Displaying each element of the 'item' array separated by a space
}
}

// Method to create a new array containing three elements from the middle of the input array
static int[] test(int[] numbers)
{
// Calculating the middle index and selecting three elements from the input array centered around the middle
return new int[] { numbers[numbers.Length / 2 - 1], numbers[numbers.Length / 2], numbers[numbers.Length / 2 + 1] };
}
}
}
```
```

Sample Output:

`New array: 7 9 11`

Flowchart:

C# Sharp Code Editor:

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