C#: Print three numbers(x, y, z) in (x+y)·z and x·y + y·z format
C# Sharp Basic: Exercise-10 with Solution
Specified Formula with Three Numbers
Write a C# Sharp program that takes three numbers (x,y,z) as input and outputs (x+y).z and x.y + y.z.
Sample Solution:
C# Sharp Code:
using System;
// This is the beginning of the Exercise10 class
public class Exercise10
{
// This is the main method where the program execution starts
public static void Main()
{
// Declaration of variables to store three numbers
int number1, number2, number3;
// Prompting the user to enter the first number
Console.Write("Enter first number - ");
// Reading the first number entered by the user and converting it to an integer
number1 = Convert.ToInt32(Console.ReadLine());
// Prompting the user to enter the second number
Console.Write("Enter second number - ");
// Reading the second number entered by the user and converting it to an integer
number2 = Convert.ToInt32(Console.ReadLine());
// Prompting the user to enter the third number
Console.Write("Enter third number - ");
// Reading the third number entered by the user and converting it to an integer
number3 = Convert.ToInt32(Console.ReadLine());
// Calculating and displaying the results using formatted output
Console.Write("Result of specified numbers {0}, {1} and {2}, (x+y)•z is {3} and x•y + y•z is {4}\n\n",
number1, number2, number3, ((number1 + number2) * number3), (number1 * number2 + number2 * number3));
}
}
Sample Output:
Enter first number - 4 Enter second number - 6 Enter third number - 2 Result of specified numbers 4, 6 and 2, (x+y)·z is 20 and x·y + y·z is 36
Flowchart:
C# Sharp Code Editor:
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