C#: Check whether a number is Strong Number or not

C# Sharp For Loop: Exercise-47 with Solution

Write a C# Sharp program to check whether a number is Strong Number or not.

Sample Solution:-

C# Sharp Code:

using System;  
public class Exercise47
{  
    public static void Main()  
{  
    int i, n, n1, s1=0,j;  
    int fact; 
	
	Console.Write("\n\n");
    Console.Write("Check whether a number is Strong Number or not:\n");
    Console.Write("-------------------------------------------------");
    Console.Write("\n\n");	

/* If sum of factorial of digits is equal to original number then it is Strong number */
  
    Console.Write("Input a number to check whether it is Strong number: ");  
    n = Convert.ToInt32(Console.ReadLine());  
    n1 = n;  
 
    for(j=n;j>0;j=j/10) 
    {  
  
        fact = 1;  
        for(i=1; i<=j % 10; i++)  
        {  
            fact = fact * i;  
        }  
         s1 = s1 + fact;  
 
    }  
  
    if(s1==n1)  
    {  
        Console.Write("\n{0} is Strong number.\n\n", n1);  
    }  
    else  
    {  
        Console.Write("\n{0} is not Strong number.\n\n", n1);  
    }  
}  
} 

Sample Output:

Check whether a number is Strong Number or not:                                                             
-------------------------------------------------                                                           
Input a number to check whether it is Strong number: 2                                                      
2 is Strong number.

Flowchart:

C# Sharp Code Editor:

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