C#: Find Strong Numbers within a range of numbers

C# Sharp For Loop: Exercise-48 with Solution

Write a C# Sharp program to find Strong Numbers within a range of numbers.

Visual Presentation:

Sample Solution:

C# Sharp Code:

using System;  // Importing necessary namespace

public class Exercise48  // Declaration of the Exercise48 class
{  
    public static void Main()  // Main method, entry point of the program
    {  
        // Declaration of variables
        int i, n1, s1 = 0, j, k, en, sn;  
        int fact; 

        // Displaying information about finding Strong Numbers within a range
        Console.Write("\n\n");
        Console.Write("Find Strong Numbers within a range of numbers:\n");
        Console.Write("------------------------------------------------");
        Console.Write("\n\n");	

        // Prompting user to input the starting and ending range of numbers
        Console.Write("Input starting range of numbers: ");  
        sn = Convert.ToInt32(Console.ReadLine());  // Reading starting range

        Console.Write("Input ending range of numbers: ");  
        en = Convert.ToInt32(Console.ReadLine());  // Reading ending range

        Console.Write("\n\nThe Strong numbers are :\n");  // Displaying the heading

        // Loop to find and display the Strong numbers within the specified range
        for (k = sn; k <= en; k++)
        {
            n1 = k;  // Storing the original number for comparison
            s1 = 0;  // Initializing sum of factorials

            // Loop to calculate the factorial sum of individual digits of the number
            for (j = k; j > 0; j = j / 10) 
            {  
                fact = 1;  // Initializing factorial as 1 for each new digit

                // Loop to calculate the factorial of each digit
                for (i = 1; i <= j % 10; i++)  
                {  
                    fact = fact * i;  // Calculating factorial
                }  
                s1 = s1 + fact;  // Accumulating the factorial sum
            }  

            // Checking if the sum of factorial of digits is equal to the original number
            if (s1 == n1)  
            {
                Console.Write("{0}  ", n1);  // Displaying Strong number
            } 
        }  

        Console.Write("\n\n");  // Adding newline after displaying Strong numbers
    }  
}
 

Sample Output:

Find Strong Numbers within a range of numbers:                                                              
------------------------------------------------                                                            
Input starting range of number : 0                                                                          
Input ending range of number: 1000                                                                          
The Strong numbers are :                                                                                    
0  1  2  145

Flowchart:

C# Sharp Code Editor:

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