C#: Closest Palindrome Number
C# Sharp Math: Exercise-25 with Solution
Write a C# Sharp program to find the closest palindrome number of an integer. If there are two palindrome numbers in absolute distance return the smallest number.
Sample Solution:
C# Sharp Code:
using System;
using System.Linq;
namespace exercises
{
class Program
{
static void Main(string[] args)
{
int n = 120;
Console.WriteLine("Original number: " + n);
Console.WriteLine("Closest Palindrome number of the said number: " + test(n));
n = 321;
Console.WriteLine("\nOriginal number: " + n);
Console.WriteLine("Closest Palindrome number of the said number: " + test(n));
n = 43;
Console.WriteLine("\nOriginal number: " + n);
Console.WriteLine("Closest Palindrome number of the said number: " + test(n));
n = 1234;
Console.WriteLine("\nOriginal number: " + n);
Console.WriteLine("Closest Palindrome number of the said number: " + test(n));
}
public static int test(int num)
{
if (is_Palindrome(num)) return num;
for (int i = 1; i <= num; i++)
{
if (is_Palindrome(num - i)) return num - i;
if (is_Palindrome(num + i)) return num + i;
}
return 0;
}
public static bool is_Palindrome(int n)
{
string num = n.ToString();
for (int i = 0; i < num.Length / 2; i++)
{
if (num[i] != num[num.Length - i - 1])
return false;
}
return true;
}
}
}
Sample Output:
Original number: 120 Closest Palindrome number of the said number: 121 Original number: 321 Closest Palindrome number of the said number: 323 Original number: 43 Closest Palindrome number of the said number: 44 Original number: 1234 Closest Palindrome number of the said number: 1221
Flowchart:
C# Sharp Code Editor:
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