# Java Exercises: Find the difference between the largest integer and the smallest integer which are created by 8 numbers from 0 to 9

## Java Basic: Exercise-231 with Solution

Write a Java program to find the difference between the largest integer and the smallest integer which are created by 8 numbers from 0 to 9. The number that can be rearranged shall start with 0 as in 00135668.

Input:

Data is a sequence of 8 numbers (numbers from 0 to 9).
Output:
The difference between the largest integer and the smallest integer.

Pictorial Presentation: Sample Solution:

Java Code:

`````` import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Input an integer created by 8 numbers from 0 to 9:");
String s = sc.next();
int[] num = new int;
for(int i=0;i<8;i++){
num[i] = Integer.valueOf(s.substring(i,i+1));
}
Arrays.sort(num);
int a = 0;
int b = 0;
int c = 1;
for(int i=0;i<8;i++){
a += num[i]*c;
b += num[7-i]*c;
c *= 10;
}
System.out.println("Difference between the largest and the smallest integer from the given integer:");
System.out.println(a-b);
}
}
```
```

Sample Output:

```Input an integer created by 8 numbers from 0 to 9:
567894321
Difference between the largest and the smallest integer from the given integer:
75308643
```

Flowchart: Java Code Editor:

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## Java: Tips of the Day

Java: ConvertInputStreamToString

Converts InputStream to a String.

```public static String convertInputStreamToString(final InputStream in) throws IOException {
ByteArrayOutputStream result = new ByteArrayOutputStream();
byte[] buffer = new byte;
int length;
while ((length = in.read(buffer)) != -1) {
result.write(buffer, 0, length);
}
return result.toString(StandardCharsets.UTF_8.name());
}
```

Ref: https://bit.ly/2N1GDss