# Java Exercises: Find the difference between the largest integer and the smallest integer which are created by 8 numbers from 0 to 9

## Java Basic: Exercise-231 with Solution

Write a Java program to find the difference between the largest integer and the smallest integer which are created by 8 numbers from 0 to 9. The number that can be rearranged shall start with 0 as in 00135668.

**Input:**

Data is a sequence of 8 numbers (numbers from 0 to 9).

**Output:**

The difference between the largest integer and the smallest integer.

**Pictorial Presentation:**

**Sample Solution:**

**Java Code:**

```
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Input an integer created by 8 numbers from 0 to 9:");
String s = sc.next();
int[] num = new int[8];
for(int i=0;i<8;i++){
num[i] = Integer.valueOf(s.substring(i,i+1));
}
Arrays.sort(num);
int a = 0;
int b = 0;
int c = 1;
for(int i=0;i<8;i++){
a += num[i]*c;
b += num[7-i]*c;
c *= 10;
}
System.out.println("Difference between the largest and the smallest integer from the given integer:");
System.out.println(a-b);
}
}
```

Sample Output:

Input an integer created by 8 numbers from 0 to 9: 567894321 Difference between the largest and the smallest integer from the given integer: 75308643

**Flowchart: **

**Java Code Editor:**

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## Java: Tips of the Day

** Count the number of occurrences of a char in a String:**

int count = StringUtils.countMatches("a.b.c.d", ".");

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