Java Exercises: Compute the sum of first n given prime numbers
Java Basic: Exercise-232 with Solution
Write a Java program to compute the sum of first n given prime numbers.
Input:
n ( n ≤ 10000). Input 0 to exit the program.
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.*;
public class Main {
public static void main(String[] args) throws java.io.IOException{
Scanner scan = new Scanner(System.in);
int count=0;
int sum=0;
System.out.println("Input a number (n<=10000) to compute the sum:");
int n=scan.nextInt();
for(int i=2;;i++){
if(prime(i)){
count++;
sum+=i;
if(count==n)break;
}
}
System.out.println("Sum of first "+n+" prime numbers:");
System.out.println(sum);
}
public static boolean prime (int n){
if(n==1)return false;
for(int i=2;i<=Math.sqrt(n);i++)
if(n%i==0)return false;
return true;
}
}
Sample Output:
Input a number (n<=10000) to compute the sum: 100 Sum of first 100 prime numbers: 24133
Flowchart:

Java Code Editor:
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Previous: Write a Java program to find the difference between the largest integer and the smallest integer which are created by 8 numbers from 0 to 9. The number that can be rearranged shall start with 0 as in 00135668.
Next: Write a Java program that accept a even number (n should be greater than or equal to 4 and less than or equal to 50,000, Goldbach number) from the user and create a combinations that express the given number as a sum of two prime numbers. Print the number of combinations.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
Java: Tips of the Day
Java: Anagrams
Generates all anagrams of a string.
public static List<String> anagrams(String input) { if (input.length() <= 2) { return input.length() == 2 ? Arrays.asList(input, input.substring(1) + input.substring(0, 1)) : Collections.singletonList(input); } return IntStream.range(0, input.length()) .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1))) .flatMap(entry -> anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1)) .stream() .map(s -> entry.getValue() + s)) .collect(Collectors.toList()); }
Ref: https://bit.ly/3rvAdAK
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