Java: Display the pattern like a diamond
Java Conditional Statement: Exercise-21 with Solution
Write a Java program to display the pattern like a diamond.
Test Data
Input number of rows (half of the diamond) :7
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise21 {
public static void main(String[] args)
{
int i,j,r;
System.out.print("Input number of rows (half of the diamond) : ");
Scanner in = new Scanner(System.in);
r = in.nextInt();
for(i=0;i<=r;i++)
{
for(j=1;j<=r-i;j++)
System.out.print(" ");
for(j=1;j<=2*i-1;j++)
System.out.print("*");
System.out.print("\n");
}
for(i=r-1;i>=1;i--)
{
for(j=1;j<=r-i;j++)
System.out.print(" ");
for(j=1;j<=2*i-1;j++)
System.out.print("*");
System.out.print("\n");
}
}
}
Sample Output:
Input number of rows (half of the diamond) : 7 * *** ***** ******* ********* *********** ************* *********** ********* ******* ***** *** *
Flowchart:

Java Code Editor:
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Previous: Write a program in Java to print the Floyd's Triangle.
Next: Write a Java program to display Pascal's triangle.
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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