Java: Find Vowel or Consonant

Java Conditional Statement: Exercise-8 with Solution

Write a Java program that requires the user to enter a single character from the alphabet. Print Vowel or Consonant, depending on user input. If the user input is not a letter (between a and z or A and Z), or is a string of length > 1, print an error message.

Test Data
Input an alphabet: p

Pictorial Presentation:

Java conditional statement Exercises: Find Vowel or Consonant

Sample Solution:

Java Code:

import java.util.Scanner;
public class Exercise8 {

  public static void main(String[] args)
        Scanner in = new Scanner(System.in);

        System.out.print("Input an alphabet: ");
        String input = in.next().toLowerCase();

        boolean uppercase = input.charAt(0) >= 65 && input.charAt(0) <= 90;
        boolean lowercase = input.charAt(0) >= 97 && input.charAt(0) <= 122;
        boolean vowels = input.equals("a") || input.equals("e") || input.equals("i")
                || input.equals("o") || input.equals("u");

        if (input.length() > 1)
            System.out.println("Error. Not a single character.");
        else if (!(uppercase || lowercase))
            System.out.println("Error. Not a letter. Enter uppercase or lowercase letter.");
        else if (vowels)
            System.out.println("Input letter is Vowel");
            System.out.println("Input letter is Consonant");

Sample Output:

Input an alphabet: P                                                                                          
Input letter is Consonant 


Flowchart: Java Conditional Statement Exercises - Find Vowel or Consonant

Java Code Editor:

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