Java: Find Vowel or Consonant
Java Conditional Statement: Exercise-8 with Solution
Write a Java program that requires the user to enter a single character from the alphabet. Print Vowel or Consonant, depending on user input. If the user input is not a letter (between a and z or A and Z), or is a string of length > 1, print an error message.
Test Data
Input an alphabet: p
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise8 {
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Input an alphabet: ");
String input = in.next().toLowerCase();
boolean uppercase = input.charAt(0) >= 65 && input.charAt(0) <= 90;
boolean lowercase = input.charAt(0) >= 97 && input.charAt(0) <= 122;
boolean vowels = input.equals("a") || input.equals("e") || input.equals("i")
|| input.equals("o") || input.equals("u");
if (input.length() > 1)
{
System.out.println("Error. Not a single character.");
}
else if (!(uppercase || lowercase))
{
System.out.println("Error. Not a letter. Enter uppercase or lowercase letter.");
}
else if (vowels)
{
System.out.println("Input letter is Vowel");
}
else
{
System.out.println("Input letter is Consonant");
}
}
}
Sample Output:
Input an alphabet: P Input letter is Consonant
Flowchart:

Java Code Editor:
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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