Java: Test a year is a leap year or not

Last update on April 10 2025 05:38:13 (UTC/GMT +8 hours)

Check Leap Year

Write a Java program that takes a year from the user and prints whether it is a leap year or not.

Test Data
Input the year: 2016

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.Scanner;
public class Exercise9 {

    
  public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);

        System.out.print("Input the year: ");
        int year = in.nextInt();

        boolean x = (year % 4) == 0;
        boolean y = (year % 100) != 0;
        boolean z = ((year % 100 == 0) && (year % 400 == 0));

        if (x && (y || z))
        {
            System.out.println(year + " is a leap year");
        }
        else
        {
            System.out.println(year + " is not a leap year");
        }
    }
}

Sample Output:

Input the year: 2016                                                                                          
2016 is a leap year

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Java program to check whether a year is a leap year using nested conditional statements and the ternary operator.
• Write a Java program to iterate over a range of years and output only the leap years among them.
• Write a Java program to determine leap year status by using modulo arithmetic and output a message for non-numeric input.
• Write a Java program to implement leap year checking with error handling for invalid year inputs.

Java Code Editor:

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