# Remove duplicates from list of integers using Lambda expression in Java

## Java Lambda Program: Exercise-7 with Solution

Write a Java program to implement a lambda expression to remove duplicates from a list of integers.

Sample Solution:

Java Code:

``````import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Main {
public static void main(String[] args) {
// Create a list of integers with duplicates
List<Integer> nums = Arrays.asList(1, 2, 3, 3, 4, 3, 2, 5, 6, 1, 7, 7, 8, 10);
// Print the list
System.out.println("List elements " + nums);
// Remove duplicates using lambda expression
List<Integer> unique_nums = new ArrayList<>();
nums.stream()
.distinct()

// Print the list without duplicates
System.out.println("\nList elements without duplicates: " + unique_nums);
}
}
``````

Sample Output:

```List elements [1, 2, 3, 3, 4, 3, 2, 5, 6, 1, 7, 7, 8, 10]

List elements without duplicates: [1, 2, 3, 4, 5, 6, 7, 8, 10]
```

Explanation:

In the above exercise we use the stream() method on the nums list to convert it into a stream. We call the distinct() method to filter out duplicate elements. The distinct() method ensures that only distinct elements are retained in the stream.

Finally, we use the forEach() method and a lambda expression unique_nums::add to add each unique element to the unique_nums list.

Flowchart:

Live Demo:

Java Code Editor:

Improve this sample solution and post your code through Disqus

Java Lambda Exercises Previous: Calculate average of doubles using Lambda expression in Java.
Java Lambda Exercises Next: Calculate factorial using Lambda expression in Java.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿