Java: Generate random integers in a specific range
Java Numbers: Exercise-3 with Solution
Write a Java program to generate random integers in a specific range.
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.Scanner;
public class Example3 {
public static void main( String args[] ){
Scanner sc = new Scanner( System.in );
System.out.print("Input the starting number of the range: ");
int rsnum = sc.nextInt();
System.out.print("Input the ending number of the range: ");
int renum = sc.nextInt();
int random_num = rsnum + (int)(Math.random() * ((renum - rsnum) + 1));
System.out.println(random_num);
}
}
Sample Output:
Input the starting number of the range: 5 Input the ending number of the range: 25 10
Flowchart:

Java Code Editor:
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Previous: Write a Java program to classify Abundant, deficient and perfect number (integers) between 1 to 10,000.
Next: Write a Java program to generate and show all Kaprekar numbers less than 1000.
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Java: Tips of the Day
IsPowerOfTwo
Checks if a value is positive power of two.
To understand how it works let's assume we made a call IsPowerOfTwo(4).
As value is greater than 0, so right side of the && operator will be evaluated.
The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.
The result of (value & value) is value. 100 & 100 => 100.
This will value the expression to true as value is equal to value.
public static boolean isPowerOfTwo(final int value) { return value > 0 && ((value & (~value + 1)) == value); }
Ref: https://bit.ly/3sA5d4I
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