w3resource

Java: Generate random integers in a specific range

Java Numbers: Exercise-3 with Solution

Write a Java program to generate random integers in a specific range.

Pictorial Presentation:

Java: Generate random integers in a specific range

Sample Solution:

Java Code:

import java.util.Scanner;
public class Example3  {

      public static void main( String args[] ){ 
	    Scanner sc = new Scanner( System.in ); 
        System.out.print("Input the starting number of the range: "); 
        int rsnum = sc.nextInt(); 
        System.out.print("Input the ending number of the range: "); 
        int renum = sc.nextInt(); 
	    int random_num = rsnum + (int)(Math.random() * ((renum - rsnum) + 1));
	    System.out.println(random_num);
     }  
}

Sample Output:

Input the starting number of the range: 5                                                                     
Input the ending number of the range: 25                                                                      
10 

Flowchart:

Flowchart: Generate random integers in a specific range

Java Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a Java program to classify Abundant, deficient and perfect number (integers) between 1 to 10,000.
Next: Write a Java program to generate and show all Kaprekar numbers less than 1000.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

Java: Tips of the Day

IsPowerOfTwo

Checks if a value is positive power of two.

To understand how it works let's assume we made a call IsPowerOfTwo(4).

As value is greater than 0, so right side of the && operator will be evaluated.

The result of (~value + 1) is equal to value itself. ~100 + 001 => 011 + 001 => 100. This is equal to value.

The result of (value & value) is value. 100 & 100 => 100.

This will value the expression to true as value is equal to value.

public static boolean isPowerOfTwo(final int value) {
    return value > 0 && ((value & (~value + 1)) == value);
}

Ref: https://bit.ly/3sA5d4I

 





We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook