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JavaScript: Filter out the non-unique values in an array, based on a provided comparator function

JavaScript fundamental (ES6 Syntax): Exercise-23 with Solution

Write a JavaScript program to filter out the non-unique values in an array, based on a provided comparator function.


Note: The comparator function takes four arguments: the values of the two elements being compared and their indexes.

  • Use Array.prototype.filter() and Array.prototype.every() to create an array containing only the unique values, based on the comparator function, fn.
  • The comparator function takes four arguments: the values of the two elements being compared and their indexes.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const filter_Non_UniqueBy = (arr, fn) =>
  arr.filter((v, i) => arr.every((x, j) => (i === j) === fn(v, x, i, j)));

console.log(filter_Non_UniqueBy(
  [
    { id: 0, value: 'a' },
    { id: 1, value: 'b' },
    { id: 2, value: 'c' },
    { id: 1, value: 'd' },
    { id: 0, value: 'e' }
  ],
  (a, b) => a.id == b.id
));

Sample Output:

[{"id":2,"value":"c"}]

Flowchart:

flowchart: Filter out the non-unique values in an array, based on a provided comparator function

Live Demo:

See the Pen javascript-basic-exercise-1-23 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

How to remove a specific item from an array?

Find the index of the array element you want to remove using indexOf, and then remove that index with splice.

The splice() method changes the contents of an array by removing existing elements and/or adding new elements.

const array = [2, 5, 9];

console.log(array);

const index = array.indexOf(5);
if (index > -1) {
  array.splice(index, 1);
}

// array = [2, 9]
console.log(array);

The second parameter of splice is the number of elements to remove. Note that splice modifies the array in place and returns a new array containing the elements that have been removed.

For the reason of completeness, here are functions. The first function removes only a single occurrence (i.e. removing the first match of 5 from [2,5,9,1,5,8,5]), while the second function removes all occurrences:

function removeItemOnce(arr, value) {
  var index = arr.indexOf(value);
  if (index > -1) {
    arr.splice(index, 1);
  }
  return arr;
}

function removeItemAll(arr, value) {
  var i = 0;
  while (i < arr.length) {
    if (arr[i] === value) {
      arr.splice(i, 1);
    } else {
      ++i;
    }
  }
  return arr;
}
//Usage
console.log(removeItemOnce([2,5,9,1,5,8,5], 5))
console.log(removeItemAll([2,5,9,1,5,8,5], 5))

Ref: https://bit.ly/2N9nKRp