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JavaScript: Filter out all values from an array for which the comparator function does not return true

JavaScript fundamental (ES6 Syntax): Exercise-74 with Solution

Write a JavaScript program to filter out all values from an array for which the comparator function does not return true.

  • Use Array.prototype.filter() and Array.prototype.findIndex() to find the appropriate values.
  • Omit the last argument, comp, to use a default strict equality comparator.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const differenceWith = (arr, val, comp) => arr.filter(a => val.findIndex(b => comp(a, b)) === -1);
console.log(differenceWith([1, 1.2, 1.5, 3, 0], [1.9, 3, 0], (a, b) => Math.round(a) === Math.round(b)));

Sample Output:

[1,1.2]

Flowchart:

flowchart: Filter out all values from an array for which the comparator function does not return trues

Live Demo:

See the Pen javascript-basic-exercise-74-1 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

Returns an array of n-tuples of consecutive elements

Example:

const tips_arr = (n, arr) =>  n > arr.length ? [] : arr.slice(n - 1).map((v, i) =>[...arr.slice(i, i + n - 1), v]);
console.log(tips_arr(2, [1, 2, 3, 4, 5])); 
console.log(tips_arr(3, [1, 2, 3, 4, 5]));
console.log(tips_arr(5, [1, 2, 3, 4]));

Output:

[[1, 2], [2, 3], [3, 4], [4, 5]]
[[1, 2, 3], [2, 3, 4], [3, 4, 5]]
[]