JavaScript: Get the n maximum elements from the provided array
JavaScript fundamental (ES6 Syntax): Exercise-87 with Solution
Write a JavaScript program to get the n maximum elements from the provided array. If n is greater than or equal to the provided array's length, then return the original array(sorted in descending order).
- Use Array.prototype.sort() combined with the spread operator (...) to create a shallow clone of the array and sort it in descending order.
- Use Array.prototype.slice() to get the specified number of elements.
- Omit the second argument, n, to get a one-element array.
- If n is greater than or equal to the provided array's length, then return the original array (sorted in descending order).
Sample Solution:
JavaScript Code:
//#Source https://bit.ly/2neWfJ2
const maxN = (arr, n = 1) => [...arr].sort((a, b) => b - a).slice(0, n);
console.log(maxN([1, 2, 3]));
console.log(maxN([1, 2, 3], 2));
Sample Output:
[3] [3,2]
Pictorial Presentation:
Flowchart:

Live Demo:
See the Pen javascript-basic-exercise-87-1 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to get the maximum value of an array, after mapping each element to a value using the provided function.
Next: Write a JavaScript program to get the median of an array of numbers.
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JavaScript: Tips of the Day
Chunks an array into n smaller arrays
Example:
const tips_chunkIntoN = (arr, n) => { const size = Math.ceil(arr.length / n); return Array.from({ length: n }, (v, i) => arr.slice(i * size, i * size + size) ); } console.log(tips_chunkIntoN([1, 2, 3, 4, 5, 6, 7,8], 4));
Output:
[[1,2],[3,4],[5,6],[7,8]]
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