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JavaScript: Returns a passed string with letters in alphabetical order

JavaScript Function: Exercise-4 with Solution

Write a JavaScript function that returns a passed string with letters in alphabetical order.
Example string: 'webmaster'
Expected Output: 'abeemrstw'

Note: Assume punctuation and numbers symbols are not included in the passed string..

Pictorial Presentation:

JavaScript: Returns a passed string with letters in alphabetical order

Sample Solution: -

HTML Code:

<!DOCTYPE html>
<html>
<head>
<meta charset=utf-8 />
<title>Returns a passed string with letters in alphabetical order</title>
</head>
<body>
  
</body>
</html>

JavaScript Code:

function alphabet_order(str)
  {
return str.split('').sort().join('');
  }
console.log(alphabet_order("webmaster"));

Sample Output:

abeemrstw

Explanation:

The split() method is used to split a String object into an array of strings by separating the string into substrings.
Code : console.log('32243'.split(""));
Output : ["3", "2", "2", "4", "3"]

The sort() method is used to sort the elements of an array in place and returns the array.
Code : console.log(["3", "2", "2", "4", "3"].sort());
Output : ["2", "2", "3", "3", "4"]

The join() method is used to join all elements of an array into a string.
Code : console.log(["2", "2", "3", "3", "4"].join(""));
Output : "22334"

Flowchart:

Flowchart: JavaScript function: Returns a passed string with letters in alphabetical order

Live Demo:

See the Pen JavaScript -Returns a passed string with letters in alphabetical order-function-ex- 4 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript function that generates all combinations of a string.
Next: Write a JavaScript function that accepts a string as a parameter and converts the first letter of each word of the string in upper case.

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JavaScript: Tips of the Day

How to check whether a string contains a substring in JavaScript?

ECMAScript 6 introduced String.prototype.includes:

const string = "foo";
const substring = "oo";

console.log(string.includes(substring));

includes doesn't have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:

var string = "foo";
var substring = "oo";

console.log(string.indexOf(substring) !== -1);

Ref: https://bit.ly/3fFFgZv